The textbook I'm reading, Integers, Polynomials, and Rings, by Ronald Irving, states on p. 246:
A ring $R$ is called a Euclidean ring if it satisfies the following three properties:
A. There is a norm function $N$ assigning to every nonzero element $a$ of $R$ a nonnegative integer $N(a)$ and assigning to $0$ a value $N(0)$ less than the norm of every nonzero element of $R$.
B. For any two nonzero elements $a$ and $b$ of $R$, $$N(a) \le N(ab)\;.$$
C. For any two nonzero elements $a$ and $b$ of $R$, there exist elements $q$ and $r$ such that $$b = aq + r$$ and $N(r) < N(a)$.
After this, the book builds a tower of about a half dozen theorems culminating in the unique factorization theorem for Euclidean spaces.
Now, in the ring $\mathbb{Z}[\sqrt{-5}]$, the elements $2$, $3$, $1 + \sqrt{-5}$, and $1 - \sqrt{-5}$ are irreducible, but they produce distinct factorizations of the element $6$: $$2\cdot 3 = (1 + \sqrt{-5})\cdot (1 - \sqrt{-5})\;.$$ This implies that no norm $N$ can exist for $\mathbb{Z}[\sqrt{-5}]$ that satisfies the three properties listed above.
Is there a more direct proof of the nonexistence of such norm for $\mathbb{Z}[\sqrt{-5}]$ than such a violation of unique factorization?
The question is what is meant by "a more direct proof". More direct does not mean easier. And it is certainly easier to refute UFD or PID instead of directly refuting norm-Euclidean. For example, it is easy to see that this ring is not a PID:
To show $\mathbb{Z}[\sqrt{-5}]$ is not a Euclidean domain, why suffices to show only the field norm $N(a+b\sqrt{-5})=a^2+5b^2$ doesn't work?