Lower bound for non-negative definite matrix

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I wonder if the following inequality is true, which I can not prove: $$ e^T A^{-1} \mathrm{diag}(A) \geq 1 $$ where $A$ is non-negative definite matrix, $\mathrm{diag}(A)$ is the vector of diagonal elements of $A$, and $e$ is vector of ones.

Thank you!