Magnitude of Resistance

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I have this question (attached image) and I can't seem to work out how to go about answering it, any help would be greatly appreciated!

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If the box is moving at constant speed, the net force is zero. That is, the resistance due to friction is equal in magnitude to the component of $150$ N and the component of $100$ N in the direction opposite to the friction. Because the angles are special, you should know that the component of $150$ N at $45^\circ$ in that direction is $150/\sqrt2,$ and the component of $100$ N at $30^\circ$ in that direction is $100\sqrt3/ 2$. Can you take it from here?