I'm given the maximum value of a random variable $X$ (for example $50$) and its mean, $\mathbb E(X)=20$. How do I find the upper bound to $P(X\le -10)$?
2026-04-01 09:28:45.1775035725
Markov inequality for random variables with negative values.
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Define new RV: S = 50 - R
E(S) = 30
P(R<=-10) = P(S>=60)
P(S>=60) = 30/60 = 1/2
You commented: I needed to clarify one last thing. P(50-X >= 60) <= 1/3
It should be 1/2 not 1/3.