$\mathbb R[X] /\langle X^2-1\rangle$ and $\mathbb R[X,Y]/\langle XY\rangle$ are not fields

230 Views Asked by At

I have to prove that

1) $\mathbb R[X] /\langle X^2-1\rangle$ is not a field, and

2) $\mathbb R[X,Y]/\langle XY\rangle$ is not a field.

So, I must exhibit an element $r$ from say $\mathbb R[X] /\langle X^2-1\rangle$ that has no multiplicative inverse. I don't know how to do this since I am not so sure what an element of this quotient looks like. One basic doubt that I have is: is $\langle X^2-1\rangle=\langle x^2-1\rangle$? I mean, is the fact that $X$ is in capital letters just a matter of notation?

I suppose that $r=f(x)\langle x^2-1\rangle$, where $f(x) \in \mathbb R[X]$, so $r=f(x)g(x)(x^2-1)$. If $r$ has an inverse, then $rr^{-1}=1_{\mathbb R[X] /\langle X^2-1\rangle}$. Is $\mathbb R[X] /\langle X^2-1\rangle$ a subring of $\mathbb R[X]$? In that case, $1_{\mathbb R[X] /\langle X^2-1\rangle}=1_{\mathbb R[X]}$.

I have the same type of doubts for (2). I would appreciate if someone could explain me how the quotient looks like and to suggest some hint to do the problem.

1

There are 1 best solutions below

0
On BEST ANSWER

In both cases they are not integral domains, for example in the first look at $x-1$ and $x+1$.