$ P(n) = n < 3^n - 4 $ for all $ n \ge 2$
Base case: $2 < 3^2 - 4$
$2 < 5$
Inductive step: Assume true for $n = k$, show true for $n = k + 1$
That is, assume $k < 3^{k} - 4$, and show $k + 1 < 3^{k + 1} - 4$
So,
(This is where I might be wrong)
$k + 1 < 3^k + 1 - 4$ (by IH) $\le 3^k + 3^k - 4 = 3^{k + 1} - 4$
Is this a valid proof? I guess I don't understand induction with inequalities very well.
You're very close! Your last equality was incorrect, though. Instead, $$3^k+1-4\le3^k+3^k+3^k-4=3^k\cdot 3-4=3^{k+1}-4.$$