Matrix $A =\begin{bmatrix}5/2&3/2\\-5/2&13/2\end{bmatrix}$ and $D = \begin{bmatrix}u&0\\0&v\end{bmatrix}$
I know that $D = P^{-1}AP$.
Knowing that $P^{-1}P=I$,
$D = P^{-1}AP$
$D = A$
I tried answering $u = 5/2$ and $v = 13/2$ but it was wrong.
Any help would be greatly appreciated
$AP = PD$
$P$ has column vectors $p_1,p_2$ and $PD = [p_1u, p_2 v]$
and $AP = [Ap_1,Ap_2]$
$Ap_1 = up_1$ and $Ap_2 = vp_1$ if this is true then
$Ap_1 - up_1 = 0\\ Ap_1 - u Ip_1 = 0\\ (A-u I)p_1 = 0$
and $(A- u I)$ is a singular matrix.
and if $(A-u I)$ is singular then $\det (A-u I) = 0$
and similarly $\det(A-v I) = 0$