Let $A \in M_n {(\mathbb{R})} $ such that $A+A^T=2I_n$. Prove that $\det(A)\geq 1 $. I find out the form of $A$ and, respectively, its determinant, but i can not prove that it is bigger than 1, any ideas?
2026-03-29 22:34:41.1774823681
Matrix and determinant inequality
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