It seems to be a simple question but I am a bit stuck to show
$$\|AB\|_{2,\infty} \leq \|A\| \|B\|_{2,\infty} $$
here $\|\cdot\|$ is the operator norm.
It seems to be a simple question but I am a bit stuck to show
$$\|AB\|_{2,\infty} \leq \|A\| \|B\|_{2,\infty} $$
here $\|\cdot\|$ is the operator norm.
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Each column of $AB$ is the product of $A$ and a column of $B$. So the 2-norm of each column of $AB$ is bounded by $\|A\|$ times the 2-norm of a column of $B$. So $\|AB\|_{2,\infty} \leq \|A\| \|B\|_{2,\infty}$.