Let's say I have a $1\times 2$ matrix $U$.
Working out $\text{transpose}(U) \times U$ and then $ U \times \text{transpose}(U). $
Why does one of these give a value while the other gives you a matrix.
Why does it matter where the transpose is?
Let's say I have a $1\times 2$ matrix $U$.
Working out $\text{transpose}(U) \times U$ and then $ U \times \text{transpose}(U). $
Why does one of these give a value while the other gives you a matrix.
Why does it matter where the transpose is?
Matrix multiplication is not commutative. In other words, you cannot switch around the order and get the same result.
For example, let's say you have $A$, which is a $3$ x $1$ matrix and $B$, which is a $2$ x $3$ matrix.
The product $AB$ is undefined, since the number of columns in $A$ must necessarily match up with the number of rows in $B$ (or else you couldn't compute the dot product between a row in $A$ and a column in $B$).
However, the product $BA$ is defined. It's a $2$ x $1$ matrix.
So this shows that it's simply not commutative, that the order in which you multiply matters. If thinking about this in a linear transformation sense, if you rotate and then shear, for example, this may not be the same as shearing and then rotating.