Meaning of complex conjugate

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I am reading about the Fourier series.

I understood the Fourier Series in terms of breaking down a function into a constant and a weighted series of sines and cosines.

I then read on in my text and it looked at the complex representation of a function. I am having difficulty understanding the indexes of the complex coefficients.

Could someone just check my understanding of the following from my text?

Screenshot from Sivia Elementary Scattering Theory Textbook

The highlighted line is what I am uncertain about (C^-n = C^*n)$

I know what a complex conjugate is, e.g. The complex number a + ib has the complex conjugate a -ib.

Is the meaning of the -n subscript just referring to the symmetry of the function? So if I have four elements in a Fourier series: -n2, -n, n, and n2, the complex value of term -n2 has to equal the complex conjugate of n2?

Thank you!

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What that textbook is claiming is that, if$$f(x)=\sum_{n=-\infty}^\infty c_ne^{inx}$$and $f$ is a real function (that is, for each $x$, $f(x)\in\Bbb R$), then$$(\forall n\in\Bbb Z):c_{-n}=\overline{c_n}.$$That's so because, for each $x$\begin{align}\sum_{n=-\infty}^\infty c_ne^{inx}&=f(x)\\&=\overline{f(x)}\text{ (since $f(x)\in\Bbb R$)}\\&=\overline{\sum_{n=-\infty}^\infty c_ne^{inx}}\\&=\sum_{n=-\infty}^\infty\overline{c_ne^{inx}}\\&=\sum_{n=-\infty}^\infty\overline{c_n}e^{-inx}\\&=\sum_{n=-\infty}^\infty\overline{c_{-n}}e^{inx}.\end{align}