Hey guys just want to make sure that I'm understanding this correctly:
$y''-y'+3y=2e^x+3x^2 $
has a $Y_p(x)=Axe^x+Bx^2+Cx+D$
Where we have $Axe^x$ as we have $$Y_c=c_1e^{\frac{1+\sqrt{11}}{2}}+c_2e^{\frac{1-\sqrt{11}}{2}}$$ or would it just be $Ae^x?$ Any help would be appreciated. Thanks