We are on E the vector space of continuous and 2 times differentiable functions on $[0,1]$ i.e., $C^2[0,1].$ I have the sets $V = f$ such that $f(0)=f(1)=0$ and $W = f$ such that $f=f''.$ And the function $\langle f,g\rangle = \int_0^1[{f(t)g(t)+f'(t)g'(t)}]\,dt.$ I have proven that they are complementary subspaces and that they are orthogonal by a scalar product defined as above.
With that I will be able to find the orthogonal projection of any function on $W.$
Now if I'm given another set $G_{a,b} = f$ such that $f(0)=a$ and $f(1)=b$ how can I determine $$\inf_{f\in G_{a,b}}\int_0^1\left[f^2(t)+f'^2(t)\right]dt?$$
Let $\|\cdot\|$ be the norm induced by the inner product $\langle\cdot,\cdot\rangle.$
I know it's the same as
$$\left(\inf_{f\in G_{a,b}} {\|f\|}\right)^{\!2}$$
and that
$$\inf_{f\in G_{a,b}}{\|f\|}$$
is $d(0,G)$ which is the projection of $0$ on $G.$
But $G$ is not even a subspace; I really don't know how to go about it. Any help would be appreciated, thanks!!!
You can use the Calculus of Variations here. Let $$L(f,\dot{f};t)=f^2(t)+\dot{f}^2(t). $$ Then the Euler-Lagrange equation says that you must set $$\frac{\partial L}{\partial f}+\frac{d}{dt}\,\frac{\partial L}{\partial \dot{f}}=0. $$ This becomes \begin{align*} 2f+\frac{d}{dt}\left(2\dot{f}\right)&=0\\ f+\ddot{f}&=0\\ f(t)&=A\sin(t)+B\cos(t). \end{align*} Applying $f(0)=a$ shows us that $B=a,$ so we rewrite as $$f(t)=A\sin(t)+a\cos(t).$$ Applying $f(1)=b$ shows us that \begin{align*} b&=A\sin(1)+a\cos(1)\\ b-a\cos(1)&=A\sin(1)\\ b\csc(1)-a\cot(1)&=A. \end{align*} Hence, $$f(t)=\left[b\csc(1)-a\cot(1)\right]\sin(t)+a\cos(t). $$