I am a bit stuck on this problem. How do I find the minimum number of elements n which ensure that I have at least C combinations of order r ? Basically, for a given C and r, find the minimum n which satisfies:
$\frac{n!}{r!(n-r)!} \ge C$
2026-03-21 14:00:19.1774101619
Minimum n in order to have at least C combinations of order r?
18 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in COMBINATORICS
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