The problem is in the last "$=$" sign.
In particular, $\|-f\|_p = -\|f\|_p$ is false,
if $f\neq0$.
Instead,
$$
\|-f\|_p = \|f\|_p
$$
is correct.
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Norms are absolutely homogeneous, meaning that $\lVert \alpha f \rVert = |\alpha| \lVert f \rVert$ for $\alpha \in \mathbb{R}.$ So your last equality doesn't follow. In fact $\lVert -f \rVert = \rVert f \lVert.$
No, it does not.
The problem is in the last "$=$" sign. In particular, $\|-f\|_p = -\|f\|_p$ is false, if $f\neq0$. Instead, $$ \|-f\|_p = \|f\|_p $$ is correct.