Modelling backspin pool shot

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I'm trying to derive equations for $\theta(t)$ and $r(t)$ when modelling a backspin shot in pool.

I am of the understanding that the rotational deceleration is $\ddot \theta(t)=\dfrac{m\mu_sgR}{I}$ where $\mu_s$ is the coefficient of sliding friction.

However, the values that I have for the real world gives me a crazy deceleration.

  • mass of whiteball $96$g = $0.096$kg
  • radius of whiteball $\frac{15}{16}$in = $2.38$cm = $0.0238$m
  • coefficient of sliding resistance = $0.3$
  • $g = 9.8$m/s²
  • Moment of inertia $I$ = $\frac{2}{5}mR^2$ = $0.0000218$ kg m²

Subbing all of this in gives $\ddot \theta(t)=\dfrac{0.096 \times 0.3 \times 9.8 \times 0.0238}{0.0000218}\approx 300$

Why am I getting an angular acceleration of $300$ rad / second²? A value online suggests that it should be between $5 - 15$ rad / second².