Monotonic Union of Submodule

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The theorem is:

Suppose $M$ is an $R$-module, $T$ is an index set, and for each $t \in T$, $N_t$ is a submodule of $M$. If $\{N_t\}$ is a monotonic collection, $\cup_{t\in T} N_t$ is a submodule.

Is the following proof correct?

If $a, b \in \cup_{t\in T} N_t$, then $a, b \in N_t$ for some $t$. Then $a+b\in N_t$.

If $c\in \cup_{t\in T}N_t$, then $c\in N_t$ for some $t$, then $cr\in N_t$, then $cr\in \cup_{t\in T}N_t$.

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Similar proof for the other criteria to be a module.

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Is it somewhat too trivial to be a theorem?

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Getting this out of unanswered-limbo


Yes, the proof is fine for proving that the union of a nondecreasing chain of submodules is a submodule. Although easy to prove, it turns out to be very useful. For example, it pops up when using Zorn's lemma to show rings with identity have maximal right ideals.