I need a layman's explanation on how to calculate monthly loan repayments. I don't know algebra.
To calculate the monthly repayment on £3000 with an APR of 7.9% over 10 years I'm doing the following: 3000 * 0.079 * 10 + 3000 / 120 = Monthly repayment of £44.75 & total repayable £5370
When I use an online loan calculator, £3000 with an APR of 7.9% over 10 years has a monthly repayment of £35.85 and total repayable £4297.28
Where am I going wrong with my maths? P.S Maths isn't exactly one of my strong points so a simple idiot proof explanation would be appreciated. Thanks.
Usually the calculation is at follows. Two assumptions:
Then the equation is
$$3000\cdot \left(1+\frac{0.079}{12}\right)^{120}= x\cdot \frac{\left(1+\frac{0.079}{12}\right)^{120}-1}{\frac{0.079}{12}}$$
$$x=3000\cdot \left(1+\frac{0.079}{12}\right)^{120}\cdot \frac{0.079}{ 12\cdot \left( \left(1+\frac{0.079}{12}\right)^{120}-1 \right)}$$
Solve the equation for $x$ (repayment). The calculator gets $x=36.24$
See the pictures of the parts of the table from this site. All numbers can be comprehended. There is no mystery about the numbers.
Table(1), Table(2), Table(3) ,Table(4), Table(5)
Example: Interest and principal in march 2021:
Balance in february 2021: $2916.46$
Interest in march 2021: $2916.46\cdot \frac{0.079}{12}=19.200...\approx 19.20$
Principal in march 2021: $36.24-19.20=17.04$
In general the payment can be made at the beginning at each month as well. Then the equation is
$$3000\cdot \left(1+\frac{0.079}{12}\right)^{120}= x\cdot \color{blue}{\left(1+\frac{0.079}{12}\right)}\cdot \frac{\left(1+\frac{0.079}{12}\right)^{120}-1}{\frac{0.079}{12}}$$
The calculator gets $x=36.00$