More Exacting A Wave

33 Views Asked by At

I have a strange wave and I am trying to make it an equation. These are the points I have plotted:

x y
$0$ $8$
$\arcsin\left(\frac{\sqrt{40}}{20}\right)$ $\sqrt{40}$
$\arcsin\left(\frac{\sqrt{80}}{20}\right)$ $\sqrt{80}$
$\frac{\pi}{4}$ $\sqrt{128}$
$\arcsin\left(\frac{\sqrt{80}}{10}\right)$ $\sqrt{80}$
$\arcsin\left(\frac{3\sqrt{40}}{20}\right)$ $\sqrt{40}$
$\frac{\pi}{2}$ $8$
$\frac{\pi}{2}+\arcsin\left(\frac{\sqrt{40}}{20}\right)$ $\sqrt{40}$
$\frac{\pi}{2}+\arcsin\left(\frac{\sqrt{80}}{20}\right)$ $\sqrt{80}$
$\frac{\pi}{2}+\frac{\pi}{4}$ $\sqrt{128}$
$\frac{\pi}{2}+\arcsin\left(\frac{\sqrt{80}}{10}\right)$ $\sqrt{80}$
$\frac{\pi}{2}+\arcsin\left(\frac{3\sqrt{40}}{20}\right)$ $\sqrt{40}$
$\pi$ $8$
$\pi+\arcsin\left(\frac{\sqrt{40}}{20}\right)$ $\sqrt{40}$
$\pi+\arcsin\left(\frac{\sqrt{80}}{20}\right)$ $\sqrt{80}$
$\pi+\frac{\pi}{4}$ $\sqrt{128}$
$\pi+\arcsin\left(\frac{\sqrt{80}}{10}\right)$ $\sqrt{80}$
$\pi+\arcsin\left(\frac{3\sqrt{40}}{20}\right)$ $\sqrt{40}$
$\frac{3\pi}{2}$ $8$
$\frac{3\pi}{2}+\arcsin\left(\frac{\sqrt{40}}{20}\right)$ $\sqrt{40}$
$\frac{3\pi}{2}+\arcsin\left(\frac{\sqrt{80}}{20}\right)$ $\sqrt{80}$
$\frac{3\pi}{2}+\frac{\pi}{4}$ $\sqrt{128}$
$\frac{3\pi}{2}+\arcsin\left(\frac{\sqrt{80}}{10}\right)$ $\sqrt{80}$
$\frac{3\pi}{2}+\arcsin\left(\frac{3\sqrt{40}}{20}\right)$ $\sqrt{40}$
$2\pi$ $8$

My only problem with this is that I haven't gotten to this kind of math yet, as I am only in 11th grade. I tried using a Lagrange Interpolation, but it was too chaotic. All I need is a wave that doesn't exceeds the height of $y = \sqrt{128}$ and doesn't go below $y = \sqrt{40}$ . The one reason I couldn't make this one is that the middle of the wave $y = 8$ isn't actually the midline and the wave has a higher amplitude on the top of and lower below the wave. Hopefully, you all can possibly come up with an equation. Thanks! :)

1

There are 1 best solutions below

7
On

The problem is that you have multiple waves, and a constant term. By looking at the data, and playing a little with the numbers, I've got afunction that approximates your data quite well: $$y=A[\cos(k(x+\varphi))+\cos(2k(x+\varphi))]+B$$ with $A=\frac{\sqrt {10}}2$, $B=8$, and $\varphi=\frac{\pi}4$. The blue lines (and circles) are your initial data, the red is the function.

It is also possible that you have a few more frequencies.

enter image description here