Moving divisions to the opposite side

Question

The question I have to answer is:

$\frac {4V_3} 2 = 108V$, where I need to get $V_3$ on its own.

When moving the 4 and the 2 to the other side will it be:

$(108 \cdot 2)/4$

or

$(108/4) \cdot 2 $

Answer 1

If so then we get $$V_3=\frac{2\cdot 108V}{4}=54V$$