By Bezout's identity, we know that by varying x, y, z, p, q, r over all integers, the expression $ax + by + cz + dp + eq + fr$ would yield all integers if and only if gcd(a,b,c,d,e,f) = 1 (i.e. the coefficients are setwise prime integers).
However, if we have the expression $ax^2 + by^2 + cz^2 + dxy + eyz + fxz$, then we know by Bezout's identity that the expression will evaluate to integers, however the expression will not yield all integers by varying x,y,z since the integers $x^2$, $y^2$, $z^2$, $xy$, $xz$, $yz$ are correlated.
So the problem is to know which integers will the expression $ax^2 + by^2 + cz^2 + dxy + eyz + fxz$ evaluate to?
For example the first 50 positive integer values of $3x^2 + 3y^2 + 8z^2 - 3xy$ are 3, 8, 9, 11, 12, 17, 20, 21, 27, 29, 32, 35, 36, 39, 41, 44, 47, 48, 53, 56, 57, 59, 63, 65, 68, 71, 72, 75, 80, 81, 83, 84, 89, 92, 93, 95, 99, 101, 107, 108, 111, 113, 116, 117, 119, 120, 125, 128, 129
and of $x^2 + y^2 + z^2 + xy + yz + xz$ are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 47, 48, 49, 50, 51, 52
I see that you added two forms. One of them, $x^2+y^2+z^2+yz+zx+xy,$ is regular, and represents exactly the same numbers as $u^2 + v^2 + 2 w^2,$ namely all but $4^k (16m+14).$
The other is irregular, although the other form (class) in the same genus is regular. The generic misses for $3x^2 + 3 y^2 + 8 z^2 + 3 xy$ are $$ 3k+1 \; , \; \; \; 9k+6 \; , \; \; \; 4k+2 \; , \; \; \; 4^m(16k+10) \; . \; \; \; $$ The sporadic misses I have found are $$ 5, 23, 45, 77, 173, 207, 377, 495, 647, 693, 1557, 1683, 3393, 5823. $$ There is absolutely no way to prove the above list complete.
From Alexander Schiemann's tables at LATTICES, here we have discriminant 216, where your form is in the first listed genus, of just two forms. Note that 1896: and 1898: are just identification numbers for the computer, they have no mathematical meaning. The regular form is the second, $3x^2 + 5 y^2 + 5 z^2 + 2yz + 3 zx + 3xy \; . \; $
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In comment, you mention the sum of three squares, and the numbers integrally represented in that manner.
In 1997, Irving Kaplansky and I and Alexander Schiemann found all the (reduced) positive forms that behave in the same way. These forms are "regular," meaning the numbers represented can be described by congruences. Actually, we were able to prove about 891 of these. At this point, there are still 8 forms with no proof.
I guess the thing to do is show the list of 102 diagonal regulars.
Here is a link to the article:
Here is a link to my hundred page introduction
There is a large collection of related material at TERNARY