In mutual information we have: if $x$ and $y$ are independent then $p(x,y)=p(x)p(y)$ and then $I(X;Y)=0$.
Do If $I (X;Y) = 0$ when $x$ and $y$ are not necessarily independent?
In mutual information we have: if $x$ and $y$ are independent then $p(x,y)=p(x)p(y)$ and then $I(X;Y)=0$.
Do If $I (X;Y) = 0$ when $x$ and $y$ are not necessarily independent?
Copyright © 2021 JogjaFile Inc.