mutual information equivalence

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So I am looking to show:

$$I(X;Y|Z) = I(Y;Z|X) − I(Y;Z) + I(X;Y)$$

I started with rewriting it with the sum

$$\sum_{x,y,z} p_{XYZ}\log_2\frac{p_{XY}(x,y|z)}{p_X(x|z)p_Y(y|z)}$$

But I do not really know where to go from there.

Do i need to split it up?

Cheers, Avocari