If ((n+7)(n-4)+33)/121=x than proof that x is always a fraction . How can I proof this.
2026-04-06 11:36:12.1775475372
(n+7)(n-4)+33/121 is always a fraction
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Hint: $\;121=11^2\,$ but $\;(n+7)(n-4)+33=n^2+3n+5=(n-4)^2+11(n-1)\,$ where $\,n-4\,$ and $\,n-1\,$ cannot both be multiples of $\,11\,$.