Let $\zeta = e^{2\pi i/n}$ be an $n$-th root of unity, and let $S = \{\zeta^m|m=0,1,\ldots,n-1\}$ be the corresponding sets of all $n$-th roots of unity.
Let $k \leq z$. Let $C \subseteq S$ such that $k=|C|$.
I made following conjecture, but so far I'm unable to prove it:
Then $\sum_{c\in C} c = 0$ implies that $k= |C|$ is a $\mathbb Z$-linear combination of strict divisors (divisors strictly greather than 1) of $n$.
This seems to be plausible, and I checked it up to $n=15$. For $n=15$ we have the interesting case that the converse does not hold for $k=11 = 1\cdot 5 + 2 \cdot 3$. Another observation we can use is that for $C \subset S$ we have the equivalence $$\sum_{c \in C} c = 0 \iff \sum_{d \in S \setminus C} d= 0$$ which is quite obvious when you consider that $\sum_{s\in S} s = 0$.
So can anyone prove or disprove this conjecture?
This is true, in fact slightly more is true, namely that it is a combination with positive coefficients (which is likely intended). If one allows repetitions of the roots, then the converse is true too.
This is a consequence of the main result of the following paper.
T. Y. Lam and K. H. Leung, MR 1736695 On vanishing sums of roots of unity, J. Algebra 224 (2000), no. 1, 91--109.
Below is its abstract:
Note that they allow repetitions of the roots. But for the direction you ask about this no problem.