Need an intuitive understanding for this. Topic : Permutations

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$$nPr = (n-1)Pr + r*(n-1)P(r-1)$$

Why does this formula logically work?

Take $n=5$ and $r=3$ for convenience

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You can think $nPr$ as taking $r$ balls one by one from $n$ distinguishable balls.

There are two (disjoint) options, do you take the last ball or you do not take it. The fact that this choices are disjoint is reminiscent of addition, why?
If you dont take it, then you are taking $r$ from the other $n-1.$ If you do, then you could have done it in any of the $r$ draws and the other $r-1$ balls come from the $n-1$ remaining balls. Notice that in the latter you will be multiplying because you have essentially two process linked i.e., when do i take that $n'$th ball and how do i take the remaining ones. This says that you have to multiply the choices. why?