The problem is:
For a prime number p the set of co-primes less than or equal to it is
given by {1,2,3,4,...p-1} .
We define f(x,p) 0 < x < p = 1 if and only if all the
numbers from 1 to p-1 can be written as a power of x in modulo-p arithmetic .
Let n be the largest 12-digit prime number . Find the product of
all integers j less than n such that f(j,n)=1, in modulo-n arithmetic
Can anyone give me a better explanation?
The numbers $x$ you are looking for are called primitive roots.
It is well known that the product of primitive roots of an odd prime $p \gt 3$ is $1 \mod p$.
For a proof: If $g$ is a primitive root, what can you say about $g^{-1}$?
Note: $g^{-1}$ is the number $\mod p$ such that $g g^{-1} = 1 \mod p$.