Need help in finding multiplier to solve the PDE

Question

I am trying to solve the following quasi linear partial differential equation, but I am not able to find the appropriate multiplier,

$${dx\over 2y(z-3)}={dy\over 2x-z}={dz\over y(2x-3)}$$

Thanks for the help.

Answer 1

From the first and last terms: $$\frac{dx}{2(z-3)}=\frac{dz}{2x-3}$$ or: $$(2x-3)dx=2(z-3)dz$$