Need help with the integral for this inverse Fourier transform.

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I need to calculate the following inverse Fourier transform:

$$G(t) = \frac{1}{\sqrt{2 \pi}} {\int _{- \infty} ^{+ \infty}} \dfrac{1 - e^{-i \omega T}}{i \omega} \; e^{i \omega t} \, \mathrm{d} \omega$$

with $T \in \mathrm{R}_+$

Now, the solution is supposed to be

$$ G(t) = \sqrt{\frac{\pi}{2}} \left( \mathrm{sign}(t) - \mathrm{sign}(t - T) \right)$$

but I've idea of how to get there.