$$ \int{ \frac{1}{(3t-1)(t+1)(t-2)}}{dt} $$
How many ways are there to solve this integral without using partial fractions? Thank you.
$$ \int{ \frac{1}{(3t-1)(t+1)(t-2)}}{dt} $$
How many ways are there to solve this integral without using partial fractions? Thank you.
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You can guess that there may be an antiderivative of the form $A \log(3t-1) + B \log(t+1) + C \log(t-2)$, based on the form of the denominator. (Insert absolute value signs if you are strict.) You can then differentiate back to see which values of $A, B, C$ you need to take. It turns out that $A = -3/20, B = 1/12, C = 1/15$.
Technically this doesn't answer your question, which asks for the number of ways. But now we can give a nontrivial lower bound, at least.