The geometric series given is this:
$$\sum_\limits{n=1}^\infty \frac{1}{(1+c)^n} = -2$$
I must find c to make the equation true. I used $a\over (1-r)$, substituting:
${(1+c)^{-1} \over 1 - (1+c)^{-1}} = -2$ and arrive at $c= -1/2$. This value however makes the series diverge as $r$ is not between $-1$ and $1$.
Please be so kind as to verify that there is no solution, or point me in the right direction or give the solution. Thank you very much!
The series cannot converge to $-2$ so $c$ has no solution.