What's the negation of “At least three of the sentence are false”?
The negation of "atleast 3" or $n >= 3$ is $n < 3$ or "less than 3".
But what is the negation of "atleast 1"?
My textbook says it is the negation is "for all elements", but according to this logic, it should be "less than 1"?
My textbook:
Prove this statement by contradiction: "The average of three real numbers is greater than or equal to at least one of the numbers."
Solution: Proof by contradiction. We assume that there are three real numbers $x$, $y$, and $z$ such that the average of the three numbers is less than each of the three numbers. That is (first term), (second term), and (third term).
Each term is the average of the 3 real numbers $<$ a real number, but as you can see the statement says $and$ which means all elements.
Well, depending on what exactly it is the texbook claim about all those elements, that could work. For example, the negation of:
$$\text{"The statement is false for at least element"}$$
is (by your, correct, logic):
$$\text{"The statement is false for less than $1$ element"}$$
which is to say:
$$\text{"The statement is false for no elements"}$$
and that is the same as:
$$\text{"The statement is *true* for all elements"}$$
The important thing to remember that you can only negate claims. Thus, there really is no such thing as "the negation of 'at least one'", because 'at least one' is, by itself, not a claim.