$$\int \frac{1}{1-x}dx=-ln(1-x)$$ And $$\int \frac{1}{1-x} dx = \sum_{n=0}^\infty \int x^n dx= \sum_{n=0}^\infty \frac{x^{n+1}}{n+1}=-ln(1-x)$$ Is this a new way to find power series for functions?
2026-04-20 06:07:06.1776665226
New way to find taylor series?
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