Non-degenerate distribution function: $F(ax+b)=F(cx+d)$ implies $a=c$ and $b=d$

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I'm currently stuck in a small part of a proof. Namely, if we have a non-degenerate distribution function , $F$, where

$F(ax+b)=F(cx+d)$

is valid, then $a=c$ and $b=d$.

I was trying some things with the generalised inverse , but since we have not assumed that $F$ should be strictly increasing, then it did not lead me anywhere. I don't expect it to be very complicated, but now I'm all out of ideas.

Thank you all!