I have the question: Solve simultaneously the three congruences 3x≡4(mod 7), 4x≡5(mod 8) and 5x≡6(mod 9). I have found solutions to the first one and last one, which are x≡6(mod 7) and x≡3(mod 9). However, the middle one is giving me some trouble as using the division rule I would have x≡1.25(mod 2), which would not make sense with the other congruences.
2026-04-21 11:31:39.1776771099
Non integer solutions to mod
40 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in MODULAR-ARITHMETIC
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