Let $h\colon \mathbb{R}^3 \to \mathbb{C}$, $$h(x)=\frac{1}{|x|(|x|^2+1)^{1/2}}$$
For which $p \text{ does } h \in L^p(\mathbb{R}^3)?$
In case $h \in L^2(\mathbb{R}^3)$ what is the corresponding norm?
Can you can use the residues method?
Let $h\colon \mathbb{R}^3 \to \mathbb{C}$, $$h(x)=\frac{1}{|x|(|x|^2+1)^{1/2}}$$
For which $p \text{ does } h \in L^p(\mathbb{R}^3)?$
In case $h \in L^2(\mathbb{R}^3)$ what is the corresponding norm?
Can you can use the residues method?
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The idea is to exploit radial symmetry (see here for a formal justification):
\begin{align}\|h\|_{L^p(\mathbb{R}^3)}^p&=\int_{\mathbb{R}^3}|h(x)|^pdx=\int_0^{\infty}\int_{|x|=r}|h(x)|^pdx dr=\int_0^{\infty}4\pi r^2\frac{1}{r^p(r^2+1)^{p/2}}dr=\\ &=4\pi\int_0^{\infty}\frac{r^{2-p}}{(r^2+1)^{p/2}}dr\end{align}
and now your problem is reduced to one-dimensional calculus.