If $ ||Ric||^{2}=\frac{S^{2}}{n} $can be concluded $ Ric=\frac{S}{n} $? where Ric is Ricci tensor and S is scalar curvature.
2026-05-15 01:50:01.1778809801
norm of Ricci curvature and Einstein manifold
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It is correct because $ ||Ric-\frac{S}{n}g||^{2}=||Ric||^{2}-\frac{S^{2}}{n} =0$.