Let $p,q > 3$ be primes. Prove that $(p-1)(q-1) \mid (pq)^2 + 3$ has no solutions.
This is the last part needed for a problem of a math competition and I'm looking for other solutions than in the official solutions. So any ideas would be nice! :)
Let $p,q > 3$ be primes. Prove that $(p-1)(q-1) \mid (pq)^2 + 3$ has no solutions.
This is the last part needed for a problem of a math competition and I'm looking for other solutions than in the official solutions. So any ideas would be nice! :)
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