nth root of unity problem for homework

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I'm super confused right now with this problem and any kind of mini lecture would be awesome. Thank you

Let $ω = e^{2πi/n}$ , where $n$ is a positive integer. Prove that

(a) $1 · ω · ω^2 · · · ω^{n−1} = (−1)^{n−1}$ .

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$$1\cdot\omega\cdot\omega^2\cdots\omega^{n-1}=\omega^{1+2+\ldots+(n-1)}$$

Using that $e^{\pi i}=-1$, and that $1+2+\ldots+(n-1)=\frac{n(n-1)}{2}$, the product becomes $$\omega^{\frac{n(n-1)}{2}}=e^{\frac{2\pi i}{n}\cdot\frac{n(n-1)}{2}}=(-1)^{n-1}$$