Since Rational numbers is countable it is equivalent to Natural numbers. Now the number sequences forming by more than 2 numbers is uncountable..Also here the open sets are singleton sets. So continuity doesn't fails . Hence the number of continous functions from rationals to itself is uncountable.. Is my argument is true?
2026-03-25 09:18:25.1774430305
Number of continous functions from set of all rationals to itself
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