Number of different factors

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If $n+1$ numbers $a, b, c, d, ...$ be all different, and each of them a prime number, prove that the number of different factors of the expression $a^mbcd ...$ is $(m+1)2^n-1$

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Try building every possible factor by going through every prime $a,b,\dots$ and asking yourself the following question : how many times do I want this prime to appear in my factor? Can you complete the proof with this idea?