Let $r(n)$ denote the number of different ways in which a natural number $n$ can be expressed as the sum of two squares. Is there any function $f(n)$ such that $r(n) \geq n^{f(n)}?$
2026-04-19 13:02:37.1776603757
Number of different ways that a number can be represented as the sum of two square?
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No, because there are many $n$ for which $r(n)=0$ but $n^{f(n)} \gt 0$ for any real $f(n)$