Number of equivalence classes of a proper subgroup

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Let $(G,+)$ be a group of order $2019$. How many equivalence classes does a proper subgroup of $G$ of order at least $100$ generate? Justify your answer.

EDIT: The solution involves Lagrange's theorem:

$|G|=|H|\cdot|G:H|$

$|H|=673$

Therefore, the number of equivalence classes is $|G:H|=3$.