Number of Periodic Points of the Expanding Map $E_m:S^1\to S^1$

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Question: Let $\forall m: E_m:S^1\to S^1$, $x\mapsto mx (\mod{1})$ be the expanding map of the circle. What is the number of periodic points of $E_m$ of (minimal) period $n$?

Motivation: In Barreira & Valls' Dynamical Systems: An Introduction on p. 25 it is asked to show the number of periodic points of $E_m$ with period $p=q^r$ for prime $q$ and natural $r$ is $n_m(p):=m^p-m^{p/q}$. My question is a generalization of this question, where we consider not prime powers but arbitrary natural numbers.

I thought of starting with the prime factorization of $n$, but it turns out to be a messy process because we need to think of all combinations. Any ideas or elegant proofs are welcomed.

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This is an example of Möbius inversion. The number of points with period dividing $n$ is $m^n$, so if $f_m(n)$ denotes the number of points with period exactly $n$, we have $$m^n = \sum_{d|n} f_m(d),$$ where the sum runs over all divisors of $d$. The Möbius inversion formula then tells us that $$f_m(n)=\sum_{d|n} \mu(d) m^{n/d},$$ where $\mu(d)$ is $0$ if $d$ is divisible by a square, else $(-1)$ raised to the number of prime factors of $d$. In particular $\mu(q)=-1$ for any prime $q$, which gives the special case you mentioned.