Is it true that if $\mu$ is a finite measure and $\nu$ is absolutely continuous w.r.t. $\mu$, then $\nu$ is a finite measure.
2026-04-14 01:41:47.1776130907
On absolutely continuous measures..
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No. For example, the Lebesgue measure is absolutely continuous with respect to the gaussian probability measure $$\frac1{\sqrt{2\pi}}e^{-x^2/2}dx.$$