Let $X$ be a projective algebraic surface over $\mathbb C$ and let, $\mathcal F$ be a locally free sheaf of rank $2$,Let's assume $ \mathcal F(1)$ has a section, then is it true that we have an exact sequence of the following form :
$ 0 \to \mathcal O_X \to \mathcal F(1) \to det(\mathcal F) \otimes I_Z \to 0 $
for some zero dimensional subscheme $Z$ in $X$ ?
We can think of a natural map from $\mathcal O_X \to \mathcal F(1)$, but I don't see why should it be injective ? and also why the cokernel looks like this?
Can anybody give me a reference? Or a hint to prove it?
Any help from anyone is welcome
The answer is essentially an application of Proposition 5, page 33, of Friedman's Algebraic Surfaces and Holomorphic Vector Bundles In what follows $V$ is a rank two vector bundle over a complex projective manifold $X$.
To give a global section $s$ of $\mathcal{F}(1)$ leads to a map $\phi_s \colon \mathcal{O}_X \rightarrow \mathcal{F}(1)$ defined by multiplication $f \mapsto fs$. If it had a nontrivial kernel then $s$ would be a torsion section which is not possible since $\mathcal{F}(1)$ is locally free. Hence $\phi_s$ is injective.
We then have $$ 0 \rightarrow \mathcal{O}_X \rightarrow \mathcal{F}(1) \rightarrow \operatorname{coker}(\phi_s) \rightarrow 0 $$ and if $\operatorname{coker}(\phi_s)$ is torsion free the Proposition tells us that $ \operatorname{coker}(\phi_s) \simeq L \otimes \mathcal{I}_Z$ for some $0$-dimensional subscheme $Z$ (maybe empty) and some linebundle $L$. As $Z$ has codimension two, we may coimpute the determinants from the above sequence to conclude that $$ L \simeq \det (\mathcal{F}(1)) = \det(\mathcal{F}) \otimes \mathcal{O}_X(2). $$