Consider the cubic curve $y=x^3+ax^2y+bxy^2+cy^3$. If $(t,r)$ and $(t,s)$ are two distinct points on the curve, then is it necessarily true that $t=0$ ?
2026-03-24 23:44:42.1774395882
On points with same $x$-co-ordinate on certain cubic curve
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In general, the answer is negative. This curve takes on a wide range of behaviors, as shown in the figures below.
Even without the visuals, we know that given an $x$, the resulting cubic equation in $y$ can "easily" have 3 real roots.
There is indeed a region in the parametric space of $\{ a,b,c\}$ that $x = 0$ is the only place a vertical line intersects with the curve at more than one place. I'm not going to cover that.
Consider a specific case with easy numbers. Take $\{ a,b,c \} = \{ -3, 2, 1\}$ as in the rightmost plot. At $x = 1$, the cubic equation in $y$ is trivial to solve. \begin{align*} y = 1 - 3y + 2y^2 + y^3 &\implies 0 = (1 - 2y + y^2) + (-2y + y^2 + y^3) \\ &\implies y(y+2)(y-1) + (y-1)^2 = 0\\ &\implies (y-1)(y^2 + 3y - 1) = 0 \end{align*} The roots are $y = 1$ and $\displaystyle y = \frac{-3 \pm \sqrt{13}}2$.
If you have Mathmatica® then below is the block code of the
Manipulatemodule I wrote to generate the plots above.