On the Number of Prime Numbers less than a Given Quantity - how is the Gamma function set in relation to the Pi function?

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I'm trying to understand Riemann's "Über die Anzahl der Primzahlen unter einer gegebenen Größe" ("On the Number of Prime Numbers less than a Given Quantity" in english). Here is the original work in German and here the english translation.

I'm stuck right on page 1 already at this identity:

$ \int_0^\infty e^{-nx}x^{s-1}dx = \frac{\Pi(s-1)}{n^s} $

I understand that the left side (without the "n"):

$ \int_0^\infty e^{-x}x^{s-1}dx $

is the Gamma function and the right hand side (without the denominator):

$ \Pi(s-1) $

is the Pi function - so the Gamma function when offset to coincide with the factorial.

For the gamma function holds:

$ \Gamma(n) = (n-1)! $

and for the Pi function holds:

$ \Pi(n) = n! $

and thus

$ \Pi(n-1) = (n-1)! $

which means that:

$ \Gamma(n) = \Pi(n-1) $

Which means I can write this also down like that:

$ \int_0^\infty e^{-x}x^{s-1}dx = \Pi(s-1) $

which is close to the original identity from above.

But where does the "n" come from on both sides?

I don't understand how I get from

$ \int_0^\infty e^{-x}x^{s-1}dx = \Pi(s-1) $

to

$ \int_0^\infty e^{-nx}x^{s-1}dx = \frac{\Pi(s-1)}{n^s} $

And what does the "n" mean in this context? It's neither an argument to the function nor is it the variable which we are integrating with respect to.