One way to solve $\int_{0}^{\infty}3\Big(\frac{e^{-x^3}}{x+1}+\frac{xe^{-x^3}}{x^3+1}-\frac{e^{-x^3}}{x^3+1}\Big)dx=G$

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It's a simple question we have :

$$\int_{0}^{\infty}3\Big(\frac{e^{-x^3}}{x+1}+\frac{xe^{-x^3}}{x^3+1}-\frac{e^{-x^3}}{x^3+1}\Big)dx=G$$

Where $G$ is the Gompertz constant

It has a simple antiderivative wich is equal to : $$eE_i(-x^3-1)$$

Where $E_i(x)$ is the Exponential integral

Applying the Fundamental theorem of calculus we get the desired result .

My question :

Have you another way to prove it ?

Thanks in advance for all your contributions.