I was looking at the following question: which is the stronger logic statement
The original poster provides two statements with the only difference being the order of the quantifiers as follows:
$\forall a \exists b \forall c \; Sport(a,b,c)$ (1)
&
$\forall a \forall c \exists b \;Sport(a,b,c)$ (2) where a,b represent people.
My question is, why exactly is there a difference in the "strength" of a statement due to the order of the quantifiers? I have read the answer on the aforementioned question, but I am looking for something which is a bit more concrete.
My interpretation of (1) in English is as follows:
For each person $a$, there is a sport $b$, which is shared by every other person $c$
Similarly, my interpretation of (2) in English is as follows:
For every person $a$ and $c$, there is a sport $b$ which they share
Are these two statements not equivalent? Could someone prove this?
They certainly are not equivalent. The first statement $$ \forall a\, \exists b\, \forall c\, Sport(a, b, c) \tag{1} $$ is true when and only when everybody "shares" a single sport. The second, $$ \forall a\, \forall c\, \exists b\, Sport(a, b, c) \tag{2} $$ is true only when any pair of people share some sport. This is a weaker statement than (1), because (2) applies to a broader range of states of the world than (1) does. (1) implies (2), in short, but not conversely.
Imagine a universe with three sports: basketball, polo and curling. In this universe there are 3 people: Tom, Dick and Harry. Tom and Dick share basketball; Tom and Harry share polo; Dick and Harry share curling.
Then (2) is true in this universe: any two people share a sport.
But (1) is false in this universe. (Suppose it's true. In (1), let $a$ be Tom. Then there is some sport $b$ such that $\forall c \, Sport(Tom, b, c)$. But whichever sport $b$ is taken as, there's some $c$ with whom Tom does not share that sport.)